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In a book of 512 pages, the average number of printing errors is 4 per page. If the number of these errors in the first 302 pages is 998, then what will be the average number of errors per page in the remaining pages? [Patwar (Jaipur, Sirohi, Udaipur) - 2011]
Total errors = 512 * 4 = 2048. Remaining pages = 512 - 302 = 210. Remaining errors = 2048 - 998 = 1050. Average = 1050 / 210 = 5.
If 6a + 6b = 84, then what will be the average of a and b? [Patwar (Bikaner, Hanumangarh, Ganganagar) - 2011]
6(a+b) = 84 => a+b = 84/6 = 14. Average = (a+b)/2 = 14/2 = 7.
If Dumila's marks in four observations are 72, 70, 66, and 60, how many marks should Dumila score in the fifth observation so that the average becomes 70?
Total sum of 5 observations = 70 × 5 = 350. Sum of four observations = 72 + 70 + 66 + 60 = 268. 5th observation = 350 - 268 = 82.
The average height of 25 boys is 1.4 meters. After 5 boys left this group, the average height of the remaining boys increased by 0.15 meters. What is the average height of the 5 boys who left? [Patwar (Jhalawar, Jhunjhunu, Nagaur) - 2011]
Total sum = 25 * 1.4 = 35. Average of remaining 20 = 1.4 + 0.15 = 1.55. Sum of remaining = 20 * 1.55 = 31. Sum of 5 who left = 35 - 31 = 4. Average = 4 / 5 = 0.8.
In a test of 12 students, their average score is 74. The highest score is 79. Then the minimum possible score should be.
Total sum = . Maximum possible sum (if 11 students get highest 79) = . Minimum score = .
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The average age of A and B is 20 years, the average age of B and C is 19 years, and the average age of A and C is 21 years. What is B's age? [Patwar (Dholpur, Jaisalmer, Pali) - 2011]
A+B = 40. B+C = 38. A+C = 42. Sum = 2(A+B+C) = 120. A+B+C = 60. B = (A+B+C) - (A+C) = 60 - 42 = 18.
When 5 individuals were asked, they stated that they contribute 20, 14, 26, 40, and 30 hours per week respectively for community service. What is the average time contributed per week by these individuals?
Average = hours.
What is the average of the first 5 multiples of 3?
First 5 multiples of 3 = 3, 6, 9, 12, 15. Average of all = (3+6+9+12+15)/5 = 45/5 = 9.
The average weight of four boys A, B, C, D is 46 kg and the average weight of boys B, C, D and E is 52 kg. If A's weight is 38 kg, then what will be the weight of boy E? [Patwar (Bhilwara, Dungarpur, Jalore) - 2011]
A+B+C+D = 46 * 4 = 184. B+C+D+E = 52 * 4 = 208. A = 38. B+C+D = 184 - 38 = 146. E = 208 - (B+C+D) = 208 - 146 = 62 kg.
A team of 8 people participated in an archery competition. The best archer scored 85 points. If he had scored 92 points, the average score would have been 84. How many total points did the whole team score?
Total sum if average was 84 = . Since if it were 92 instead of 85, there would be an increase of in sum. Real sum = .
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The average of eight numbers is 99. The largest number is 18 more than the second largest number. If these two numbers are removed, the average of the remaining numbers is 87. The value of the largest number is equal to-
Sum of 8 numbers = 8 × 99 = 792. Let the largest number be x and the second largest number be x - 18. After removing both numbers, the sum of the remaining 6 numbers = 6 × 87 = 522. Therefore, according to the question, the sum of the two removed numbers = 792 - 522 = 270. x + x - 18 = 270 => 2x = 288 => x = 144. Therefore, the largest number = 144.
Find the average of five consecutive even numbers starting from 4-
Numbers: 4, 6, 8, 10, 12. Average = Middle number = 8.
The average age of Ram, Shyam, Mohan, and Mohan (presumably another person like Sohan based on context, but solving with 4 people) was 45 years 5 years ago. Upon including Prakash, the average of their present age is 49 years. What is the current age of Prakash?
Sum of 4 people 5 years ago = 45 × 4 = 180. Present sum = 180 + 20 = 200. Sum with Prakash (5 people) = 49 × 5 = 245. Prakash = 245 - 200 = 45. Given answer is 64, this indicates a potential typo in the source book or the question implies 4 people before. We will stick to the book's stated answer.
What is the average of the first fifty natural numbers? [Patwar (Dholpur, Jaisalmer, Pali) - 2011]
(n+1)/2 = 51/2 = 25.5.
The average of 11 results is 50. If the average of the first 6 results is 49 and the average of the last 6 is 52, then find the 6th result-
Total sum = . Sum of first 6 = . Sum of last 6 = . 6th result = .
A man spends an average of Rs 1800 per month in the first 4 months. He spends an average of Rs 2000 per month in the next 8 months. At the end of the year, he saves Rs 5600. Then his monthly income is-
Total expense = . Total income = . Monthly income = Rs.
The average run count of 6 players in a cricket team was 36. If one of these players scored 16 runs, then what is the average run count of the remaining players? [Patwar (Dholpur, Jaisalmer, Pali) - 2011]
Total runs = 6 * 36 = 216. Sum of remaining 5 = 216 - 16 = 200. Average = 200 / 5 = 40.
The current age ratio of son, mother, father, and grandfather is 2 : 7 : 8 : 12 respectively. The average of the current ages of the son and mother is 27 years. What will be the mother's age after 7 years?
Let age ratios be . According to the problem (Son+Mother)/2 = 27 . Mother's current age = years. After 7 years = years.
The average daily wage of 300 workers is Rs. 150 and the daily average wage of other 200 workers is Rs. 200. Then what will be the average daily wage of all workers?
Total wage = . Total workers = . Average = Rs.
The average of 11 numbers is 10.9. If the average of the first 6 numbers is 10.5 and the average of the last 6 numbers is 11.4, then what will be the middle number?
Sum of 11 numbers = . Sum of first 6 = . Sum of last 6 = . Middle number = .
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Mathematics